Metamath Proof Explorer


Theorem bj-lineqi

Description: Solution of a (scalar) linear equation. (Contributed by BJ, 6-Jun-2019)

Ref Expression
Hypotheses bj-lineqi.a ⊢ φ → A ∈ ℂ
bj-lineqi.b ⊢ φ → B ∈ ℂ
bj-lineqi.x ⊢ φ → X ∈ ℂ
bj-lineqi.y ⊢ φ → Y ∈ ℂ
bj-lineqi.n0 ⊢ φ → A ≠ 0
bj-lineqi.1 ⊢ φ → A ⁢ X + B = Y
Assertion bj-lineqi ⊢ φ → X = Y − B A

Proof

Step Hyp Ref Expression
1 bj-lineqi.a ⊢ φ → A ∈ ℂ
2 bj-lineqi.b ⊢ φ → B ∈ ℂ
3 bj-lineqi.x ⊢ φ → X ∈ ℂ
4 bj-lineqi.y ⊢ φ → Y ∈ ℂ
5 bj-lineqi.n0 ⊢ φ → A ≠ 0
6 bj-lineqi.1 ⊢ φ → A ⁢ X + B = Y
7 1 2 3 4 5 lineq ⊢ φ → A ⁢ X + B = Y ↔ X = Y − B A
8 6 7 mpbid ⊢ φ → X = Y − B A