Metamath Proof Explorer


Theorem bj-ssbid1

Description: A special case of sbequ1 . (Contributed by BJ, 22-Dec-2020)

Ref Expression
Assertion bj-ssbid1 ⊢ φ → x x φ

Proof

Step Hyp Ref Expression
1 equid ⊢ x = x
2 sbequ1 ⊢ x = x → φ → x x φ
3 1 2 ax-mp ⊢ φ → x x φ