Metamath Proof Explorer


Theorem breq12d

Description: Equality deduction for a binary relation. (Contributed by NM, 8-Feb-1996) (Proof shortened by Andrew Salmon, 9-Jul-2011)

Ref Expression
Hypotheses breq1d.1 φ A = B
breq12d.2 φ C = D
Assertion breq12d φ A R C B R D

Proof

Step Hyp Ref Expression
1 breq1d.1 φ A = B
2 breq12d.2 φ C = D
3 breq12 A = B C = D A R C B R D
4 1 2 3 syl2anc φ A R C B R D