Metamath Proof Explorer


Theorem breq2d

Description: Equality deduction for a binary relation. (Contributed by NM, 8-Feb-1996)

Ref Expression
Hypothesis breq1d.1 φ A = B
Assertion breq2d φ C R A C R B

Proof

Step Hyp Ref Expression
1 breq1d.1 φ A = B
2 breq2 A = B C R A C R B
3 1 2 syl φ C R A C R B