Metamath Proof Explorer


Theorem breq2d

Description: Equality deduction for a binary relation. (Contributed by NM, 8-Feb-1996)

Ref Expression
Hypothesis breq1d.1 φA=B
Assertion breq2d φCRACRB

Proof

Step Hyp Ref Expression
1 breq1d.1 φA=B
2 breq2 A=BCRACRB
3 1 2 syl φCRACRB