Metamath Proof Explorer


Theorem cbv3v2

Description: Version of cbv3 with two disjoint variable conditions, which does not require ax-11 nor ax-13 . (Contributed by BJ, 24-Jun-2019) (Proof shortened by Wolf Lammen, 30-Aug-2021)

Ref Expression
Hypotheses cbv3v2.nf ⊢ Ⅎ x ψ
cbv3v2.1 ⊢ x = y → φ → ψ
Assertion cbv3v2 ⊢ ∀ x φ → ∀ y ψ

Proof

Step Hyp Ref Expression
1 cbv3v2.nf ⊢ Ⅎ x ψ
2 cbv3v2.1 ⊢ x = y → φ → ψ
3 1 2 spimfv ⊢ ∀ x φ → ψ
4 3 alrimiv ⊢ ∀ x φ → ∀ y ψ