Theorem cdeqth

Description: Deduce conditional equality from a theorem. (Contributed by Mario Carneiro, 11-Aug-2016)

	Ref	Expression
Hypothesis	cdeqth.1	$$⊢\phi$$
Assertion	cdeqth	$$⊢CondEq\left(x=y\to \phi \right)$$

Proof

Step	Hyp	Ref	Expression
1		cdeqth.1	$$⊢\phi$$
2	1	a1i	$$⊢x=y\to \phi$$
3	2	cdeqi	$$⊢CondEq\left(x=y\to \phi \right)$$