Metamath Proof Explorer


Theorem chjval

Description: Value of join in CH . (Contributed by NM, 9-Aug-2000) (New usage is discouraged.)

Ref Expression
Assertion chjval ⊢ A ∈ C ℋ ∧ B ∈ C ℋ → A ∨ ℋ B = ⊥ ⁡ ⊥ ⁡ A ∪ B

Proof

Step Hyp Ref Expression
1 chsh ⊢ A ∈ C ℋ → A ∈ S ℋ
2 chsh ⊢ B ∈ C ℋ → B ∈ S ℋ
3 shjval ⊢ A ∈ S ℋ ∧ B ∈ S ℋ → A ∨ ℋ B = ⊥ ⁡ ⊥ ⁡ A ∪ B
4 1 2 3 syl2an ⊢ A ∈ C ℋ ∧ B ∈ C ℋ → A ∨ ℋ B = ⊥ ⁡ ⊥ ⁡ A ∪ B