Metamath Proof Explorer


Theorem coeq1d

Description: Equality deduction for composition of two classes. (Contributed by NM, 16-Nov-2000)

Ref Expression
Hypothesis coeq1d.1 ⊢ φ → A = B
Assertion coeq1d ⊢ φ → A ∘ C = B ∘ C

Proof

Step Hyp Ref Expression
1 coeq1d.1 ⊢ φ → A = B
2 coeq1 ⊢ A = B → A ∘ C = B ∘ C
3 1 2 syl ⊢ φ → A ∘ C = B ∘ C