Metamath Proof Explorer


Theorem coeq1d

Description: Equality deduction for composition of two classes. (Contributed by NM, 16-Nov-2000)

Ref Expression
Hypothesis coeq1d.1 φ A = B
Assertion coeq1d φ A C = B C

Proof

Step Hyp Ref Expression
1 coeq1d.1 φ A = B
2 coeq1 A = B A C = B C
3 1 2 syl φ A C = B C