Metamath Proof Explorer


Theorem coeq2d

Description: Equality deduction for composition of two classes. (Contributed by NM, 16-Nov-2000)

Ref Expression
Hypothesis coeq1d.1 ⊢ φ → A = B
Assertion coeq2d ⊢ φ → C ∘ A = C ∘ B

Proof

Step Hyp Ref Expression
1 coeq1d.1 ⊢ φ → A = B
2 coeq2 ⊢ A = B → C ∘ A = C ∘ B
3 1 2 syl ⊢ φ → C ∘ A = C ∘ B