Metamath Proof Explorer


Theorem dfss5

Description: Alternate definition of subclass relationship: a class A is a subclass of another class B iff each element of A is equal to an element of B . (Contributed by AV, 13-Nov-2020)

Ref Expression
Assertion dfss5 ⊢ A ⊆ B ↔ ∀ x ∈ A ∃ y ∈ B x = y

Proof

Step Hyp Ref Expression
1 dfss3 ⊢ A ⊆ B ↔ ∀ x ∈ A x ∈ B
2 clel5 ⊢ x ∈ B ↔ ∃ y ∈ B x = y
3 2 ralbii ⊢ ∀ x ∈ A x ∈ B ↔ ∀ x ∈ A ∃ y ∈ B x = y
4 1 3 bitri ⊢ A ⊆ B ↔ ∀ x ∈ A ∃ y ∈ B x = y