Metamath Proof Explorer


Theorem dfss3

Description: Alternate definition of subclass relationship. (Contributed by NM, 14-Oct-1999)

Ref Expression
Assertion dfss3 ⊢ A ⊆ B ↔ ∀ x ∈ A x ∈ B

Proof

Step Hyp Ref Expression
1 df-ss ⊢ A ⊆ B ↔ ∀ x x ∈ A → x ∈ B
2 df-ral ⊢ ∀ x ∈ A x ∈ B ↔ ∀ x x ∈ A → x ∈ B
3 1 2 bitr4i ⊢ A ⊆ B ↔ ∀ x ∈ A x ∈ B