Metamath Proof Explorer


Theorem dicelval2N

Description: Membership in value of the partial isomorphism C for a lattice K . (Contributed by NM, 25-Feb-2014) (New usage is discouraged.)

Ref Expression
Hypotheses dicval.l ⊢ ≤ ˙ = ≤ K
dicval.a ⊢ A = Atoms ⁡ K
dicval.h ⊢ H = LHyp ⁡ K
dicval.p ⊢ P = oc ⁡ K ⁡ W
dicval.t ⊢ T = LTrn ⁡ K ⁡ W
dicval.e ⊢ E = TEndo ⁡ K ⁡ W
dicval.i ⊢ I = DIsoC ⁡ K ⁡ W
dicval2.g ⊢ G = ι g ∈ T | g ⁡ P = Q
Assertion dicelval2N ⊢ K ∈ V ∧ W ∈ H ∧ Q ∈ A ∧ ¬ Q ≤ ˙ W → Y ∈ I ⁡ Q ↔ Y ∈ V × V ∧ 1 st ⁡ Y = 2 nd ⁡ Y ⁡ G ∧ 2 nd ⁡ Y ∈ E

Proof

Step Hyp Ref Expression
1 dicval.l ⊢ ≤ ˙ = ≤ K
2 dicval.a ⊢ A = Atoms ⁡ K
3 dicval.h ⊢ H = LHyp ⁡ K
4 dicval.p ⊢ P = oc ⁡ K ⁡ W
5 dicval.t ⊢ T = LTrn ⁡ K ⁡ W
6 dicval.e ⊢ E = TEndo ⁡ K ⁡ W
7 dicval.i ⊢ I = DIsoC ⁡ K ⁡ W
8 dicval2.g ⊢ G = ι g ∈ T | g ⁡ P = Q
9 1 2 3 4 5 6 7 dicelvalN ⊢ K ∈ V ∧ W ∈ H ∧ Q ∈ A ∧ ¬ Q ≤ ˙ W → Y ∈ I ⁡ Q ↔ Y ∈ V × V ∧ 1 st ⁡ Y = 2 nd ⁡ Y ⁡ ι g ∈ T | g ⁡ P = Q ∧ 2 nd ⁡ Y ∈ E
10 8 fveq2i ⊢ 2 nd ⁡ Y ⁡ G = 2 nd ⁡ Y ⁡ ι g ∈ T | g ⁡ P = Q
11 10 eqeq2i ⊢ 1 st ⁡ Y = 2 nd ⁡ Y ⁡ G ↔ 1 st ⁡ Y = 2 nd ⁡ Y ⁡ ι g ∈ T | g ⁡ P = Q
12 11 anbi1i ⊢ 1 st ⁡ Y = 2 nd ⁡ Y ⁡ G ∧ 2 nd ⁡ Y ∈ E ↔ 1 st ⁡ Y = 2 nd ⁡ Y ⁡ ι g ∈ T | g ⁡ P = Q ∧ 2 nd ⁡ Y ∈ E
13 12 anbi2i ⊢ Y ∈ V × V ∧ 1 st ⁡ Y = 2 nd ⁡ Y ⁡ G ∧ 2 nd ⁡ Y ∈ E ↔ Y ∈ V × V ∧ 1 st ⁡ Y = 2 nd ⁡ Y ⁡ ι g ∈ T | g ⁡ P = Q ∧ 2 nd ⁡ Y ∈ E
14 9 13 bitr4di ⊢ K ∈ V ∧ W ∈ H ∧ Q ∈ A ∧ ¬ Q ≤ ˙ W → Y ∈ I ⁡ Q ↔ Y ∈ V × V ∧ 1 st ⁡ Y = 2 nd ⁡ Y ⁡ G ∧ 2 nd ⁡ Y ∈ E