Metamath Proof Explorer


Theorem difeq1d

Description: Deduction adding difference to the right in a class equality. (Contributed by NM, 15-Nov-2002)

Ref Expression
Hypothesis difeq1d.1 ⊢ φ → A = B
Assertion difeq1d ⊢ φ → A ∖ C = B ∖ C

Proof

Step Hyp Ref Expression
1 difeq1d.1 ⊢ φ → A = B
2 difeq1 ⊢ A = B → A ∖ C = B ∖ C
3 1 2 syl ⊢ φ → A ∖ C = B ∖ C