Metamath Proof Explorer


Theorem difeq1d

Description: Deduction adding difference to the right in a class equality. (Contributed by NM, 15-Nov-2002)

Ref Expression
Hypothesis difeq1d.1 ⊢ ( 𝜑 → 𝐴 = 𝐵 )
Assertion difeq1d ( 𝜑 → ( 𝐴 ∖ 𝐶 ) = ( 𝐵 ∖ 𝐶 ) )

Proof

Step Hyp Ref Expression
1 difeq1d.1 ⊢ ( 𝜑 → 𝐴 = 𝐵 )
2 difeq1 ⊢ ( 𝐴 = 𝐵 → ( 𝐴 ∖ 𝐶 ) = ( 𝐵 ∖ 𝐶 ) )
3 1 2 syl ⊢ ( 𝜑 → ( 𝐴 ∖ 𝐶 ) = ( 𝐵 ∖ 𝐶 ) )