Metamath Proof Explorer


Theorem difeq1

Description: Equality theorem for class difference. (Contributed by NM, 10-Feb-1997) (Proof shortened by Andrew Salmon, 26-Jun-2011)

Ref Expression
Assertion difeq1 ( 𝐴 = 𝐵 → ( 𝐴 ∖ 𝐶 ) = ( 𝐵 ∖ 𝐶 ) )

Proof

Step Hyp Ref Expression
1 rabeq ⊢ ( 𝐴 = 𝐵 → { 𝑥 ∈ 𝐴 ∣ ¬ 𝑥 ∈ 𝐶 } = { 𝑥 ∈ 𝐵 ∣ ¬ 𝑥 ∈ 𝐶 } )
2 dfdif2 ⊢ ( 𝐴 ∖ 𝐶 ) = { 𝑥 ∈ 𝐴 ∣ ¬ 𝑥 ∈ 𝐶 }
3 dfdif2 ⊢ ( 𝐵 ∖ 𝐶 ) = { 𝑥 ∈ 𝐵 ∣ ¬ 𝑥 ∈ 𝐶 }
4 1 2 3 3eqtr4g ⊢ ( 𝐴 = 𝐵 → ( 𝐴 ∖ 𝐶 ) = ( 𝐵 ∖ 𝐶 ) )