Metamath Proof Explorer


Theorem disjALTV0

Description: The null class is disjoint. (Contributed by Peter Mazsa, 27-Sep-2021)

Ref Expression
Assertion disjALTV0 ⊢ Disj ∅

Proof

Step Hyp Ref Expression
1 br0 ⊢ ¬ u ∅ x
2 1 nex ⊢ ¬ ∃ u u ∅ x
3 nexmo ⊢ ¬ ∃ u u ∅ x → ∃* u u ∅ x
4 2 3 ax-mp ⊢ ∃* u u ∅ x
5 4 ax-gen ⊢ ∀ x ∃* u u ∅ x
6 rel0 ⊢ Rel ⁡ ∅
7 dfdisjALTV4 ⊢ Disj ∅ ↔ ∀ x ∃* u u ∅ x ∧ Rel ⁡ ∅
8 5 6 7 mpbir2an ⊢ Disj ∅