Metamath Proof Explorer


Theorem disjdif

Description: A class and its relative complement are disjoint. Theorem 38 of Suppes p. 29. (Contributed by NM, 24-Mar-1998)

Ref Expression
Assertion disjdif ⊢ A ∩ B ∖ A = ∅

Proof

Step Hyp Ref Expression
1 ssid ⊢ A ⊆ A
2 disjdifg ⊢ A ⊆ A → A ∩ B ∖ A = ∅
3 1 2 ax-mp ⊢ A ∩ B ∖ A = ∅