Metamath Proof Explorer


Theorem disjdif

Description: A class and its relative complement are disjoint. Theorem 38 of Suppes p. 29. (Contributed by NM, 24-Mar-1998)

Ref Expression
Assertion disjdif ( 𝐴 ∩ ( 𝐵 ∖ 𝐴 ) ) = ∅

Proof

Step Hyp Ref Expression
1 ssid ⊢ 𝐴 ⊆ 𝐴
2 disjdifg ⊢ ( 𝐴 ⊆ 𝐴 → ( 𝐴 ∩ ( 𝐵 ∖ 𝐴 ) ) = ∅ )
3 1 2 ax-mp ⊢ ( 𝐴 ∩ ( 𝐵 ∖ 𝐴 ) ) = ∅