Metamath Proof Explorer


Theorem ssid

Description: Any class is a subclass of itself. Exercise 10 of TakeutiZaring p. 18. (Contributed by NM, 21-Jun-1993) (Proof shortened by Andrew Salmon, 14-Jun-2011)

Ref Expression
Assertion ssid A A

Proof

Step Hyp Ref Expression
1 id x A x A
2 1 ssriv A A