Metamath Proof Explorer


Theorem disjresundif

Description: Lemma for ressucdifsn2 . (Contributed by Peter Mazsa, 24-Jul-2024)

Ref Expression
Assertion disjresundif AB=RABRB=RA

Proof

Step Hyp Ref Expression
1 resundi RAB=RARB
2 1 difeq1i RABRB=RARBRB
3 difun2 RARBRB=RARB
4 2 3 eqtri RABRB=RARB
5 disjresdif AB=RARB=RA
6 4 5 eqtrid AB=RABRB=RA