Metamath Proof Explorer


Theorem disjresundif

Description: Lemma for ressucdifsn2 . (Contributed by Peter Mazsa, 24-Jul-2024)

Ref Expression
Assertion disjresundif ( ( 𝐴 ∩ 𝐵 ) = ∅ → ( ( 𝑅 ↾ ( 𝐴 ∪ 𝐵 ) ) ∖ ( 𝑅 ↾ 𝐵 ) ) = ( 𝑅 ↾ 𝐴 ) )

Proof

Step Hyp Ref Expression
1 resundi ⊢ ( 𝑅 ↾ ( 𝐴 ∪ 𝐵 ) ) = ( ( 𝑅 ↾ 𝐴 ) ∪ ( 𝑅 ↾ 𝐵 ) )
2 1 difeq1i ⊢ ( ( 𝑅 ↾ ( 𝐴 ∪ 𝐵 ) ) ∖ ( 𝑅 ↾ 𝐵 ) ) = ( ( ( 𝑅 ↾ 𝐴 ) ∪ ( 𝑅 ↾ 𝐵 ) ) ∖ ( 𝑅 ↾ 𝐵 ) )
3 difun2 ⊢ ( ( ( 𝑅 ↾ 𝐴 ) ∪ ( 𝑅 ↾ 𝐵 ) ) ∖ ( 𝑅 ↾ 𝐵 ) ) = ( ( 𝑅 ↾ 𝐴 ) ∖ ( 𝑅 ↾ 𝐵 ) )
4 2 3 eqtri ⊢ ( ( 𝑅 ↾ ( 𝐴 ∪ 𝐵 ) ) ∖ ( 𝑅 ↾ 𝐵 ) ) = ( ( 𝑅 ↾ 𝐴 ) ∖ ( 𝑅 ↾ 𝐵 ) )
5 disjresdif ⊢ ( ( 𝐴 ∩ 𝐵 ) = ∅ → ( ( 𝑅 ↾ 𝐴 ) ∖ ( 𝑅 ↾ 𝐵 ) ) = ( 𝑅 ↾ 𝐴 ) )
6 4 5 eqtrid ⊢ ( ( 𝐴 ∩ 𝐵 ) = ∅ → ( ( 𝑅 ↾ ( 𝐴 ∪ 𝐵 ) ) ∖ ( 𝑅 ↾ 𝐵 ) ) = ( 𝑅 ↾ 𝐴 ) )