Metamath Proof Explorer


Theorem div2negd

Description: Quotient of two negatives. (Contributed by Mario Carneiro, 27-May-2016)

Ref Expression
Hypotheses div1d.1 ⊢ φ → A ∈ ℂ
divcld.2 ⊢ φ → B ∈ ℂ
divcld.3 ⊢ φ → B ≠ 0
Assertion div2negd ⊢ φ → − A − B = A B

Proof

Step Hyp Ref Expression
1 div1d.1 ⊢ φ → A ∈ ℂ
2 divcld.2 ⊢ φ → B ∈ ℂ
3 divcld.3 ⊢ φ → B ≠ 0
4 div2neg ⊢ A ∈ ℂ ∧ B ∈ ℂ ∧ B ≠ 0 → − A − B = A B
5 1 2 3 4 syl3anc ⊢ φ → − A − B = A B