Metamath Proof Explorer


Theorem dmcoeq

Description: Domain of a composition. (Contributed by NM, 19-Mar-1998)

Ref Expression
Assertion dmcoeq ⊢ dom ⁡ A = ran ⁡ B → dom ⁡ A ∘ B = dom ⁡ B

Proof

Step Hyp Ref Expression
1 eqimss2 ⊢ dom ⁡ A = ran ⁡ B → ran ⁡ B ⊆ dom ⁡ A
2 dmcosseq ⊢ ran ⁡ B ⊆ dom ⁡ A → dom ⁡ A ∘ B = dom ⁡ B
3 1 2 syl ⊢ dom ⁡ A = ran ⁡ B → dom ⁡ A ∘ B = dom ⁡ B