Theorem eqimss2

Description: Equality implies inclusion. (Contributed by NM, 23-Nov-2003)

	Ref	Expression
Assertion	eqimss2	$$⊢B=A\to A\subseteq B$$

Proof

Step	Hyp	Ref	Expression
1		eqimss	$$⊢A=B\to A\subseteq B$$
2	1	eqcoms	$$⊢B=A\to A\subseteq B$$