Theorem eqimssi

Description: Infer subclass relationship from equality. (Contributed by NM, 6-Jan-2007)

	Ref	Expression
Hypothesis	eqimssi.1	$$⊢A=B$$
Assertion	eqimssi	$$⊢A\subseteq B$$

Proof

Step	Hyp	Ref	Expression
1		eqimssi.1	$$⊢A=B$$
2		ssid	$$⊢A\subseteq A$$
3	2 1	sseqtri	$$⊢A\subseteq B$$