Theorem eqimssi

Description: Infer subclass relationship from equality. (Contributed by NM, 6-Jan-2007)

	Ref	Expression
Hypothesis	eqimssi.1	⊢ 𝐴 = 𝐵
Assertion	eqimssi	⊢ 𝐴 ⊆ 𝐵

Proof

Step	Hyp	Ref	Expression
1		eqimssi.1	⊢ 𝐴 = 𝐵
2		ssid	⊢ 𝐴 ⊆ 𝐴
3	2 1	sseqtri	⊢ 𝐴 ⊆ 𝐵