Theorem eqimss2i

Description: Infer subclass relationship from equality. (Contributed by NM, 7-Jan-2007)

	Ref	Expression
Hypothesis	eqimssi.1	⊢ 𝐴 = 𝐵
Assertion	eqimss2i	⊢ 𝐵 ⊆ 𝐴

Proof

Step	Hyp	Ref	Expression
1		eqimssi.1	⊢ 𝐴 = 𝐵
2		ssid	⊢ 𝐵 ⊆ 𝐵
3	2 1	sseqtrri	⊢ 𝐵 ⊆ 𝐴