Theorem eqimss2i

Description: Infer subclass relationship from equality. (Contributed by NM, 7-Jan-2007)

	Ref	Expression
Hypothesis	eqimssi.1	$$⊢A=B$$
Assertion	eqimss2i	$$⊢B\subseteq A$$

Proof

Step	Hyp	Ref	Expression
1		eqimssi.1	$$⊢A=B$$
2		ssid	$$⊢B\subseteq B$$
3	2 1	sseqtrri	$$⊢B\subseteq A$$