Metamath Proof Explorer


Theorem sseqtri

Description: Substitution of equality into a subclass relationship. (Contributed by NM, 28-Jul-1995)

Ref Expression
Hypotheses sseqtr.1 ⊢ 𝐴 ⊆ 𝐵
sseqtr.2 ⊢ 𝐵 = 𝐶
Assertion sseqtri 𝐴 ⊆ 𝐶

Proof

Step Hyp Ref Expression
1 sseqtr.1 ⊢ 𝐴 ⊆ 𝐵
2 sseqtr.2 ⊢ 𝐵 = 𝐶
3 2 sseq2i ⊢ ( 𝐴 ⊆ 𝐵 ↔ 𝐴 ⊆ 𝐶 )
4 1 3 mpbi ⊢ 𝐴 ⊆ 𝐶