Theorem eqimss

Description: Equality implies inclusion. (Contributed by NM, 21-Jun-1993) (Proof shortened by Andrew Salmon, 21-Jun-2011)

	Ref	Expression
Assertion	eqimss	$$⊢A=B\to A\subseteq B$$

Proof

Step	Hyp	Ref	Expression
1		eqss	$$⊢A=B\leftrightarrow \left(A\subseteq B\wedge B\subseteq A\right)$$
2	1	simplbi	$$⊢A=B\to A\subseteq B$$