Metamath Proof Explorer


Theorem efald

Description: Deduction based on reductio ad absurdum. (Contributed by Mario Carneiro, 9-Feb-2017)

Ref Expression
Hypothesis efald.1 ⊢ φ ∧ ¬ ψ → ⊥
Assertion efald ⊢ φ → ψ

Proof

Step Hyp Ref Expression
1 efald.1 ⊢ φ ∧ ¬ ψ → ⊥
2 1 inegd ⊢ φ → ¬ ¬ ψ
3 2 notnotrd ⊢ φ → ψ