Metamath Proof Explorer


Theorem elab

Description: Membership in a class abstraction, using implicit substitution. Compare Theorem 6.13 of Quine p. 44. (Contributed by NM, 1-Aug-1994)

Ref Expression
Hypotheses elab.1 A V
elab.2 x = A φ ψ
Assertion elab A x | φ ψ

Proof

Step Hyp Ref Expression
1 elab.1 A V
2 elab.2 x = A φ ψ
3 nfv x ψ
4 3 1 2 elabf A x | φ ψ