Metamath Proof Explorer
Description: Membership in a class abstraction, using implicit substitution. Compare
Theorem 6.13 of Quine p. 44. (Contributed by NM, 1-Aug-1994)
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Ref |
Expression |
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Hypotheses |
elab.1 |
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elab.2 |
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Assertion |
elab |
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Proof
Step |
Hyp |
Ref |
Expression |
1 |
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elab.1 |
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2 |
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elab.2 |
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3 |
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nfv |
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4 |
3 1 2
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elabf |
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