Metamath Proof Explorer
Description: Equality theorem for disjoint elementhood, inference version.
(Contributed by Peter Mazsa, 23-Sep-2021)
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Ref |
Expression |
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Hypothesis |
eldisjeqi.1 |
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Assertion |
eldisjeqi |
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Proof
Step |
Hyp |
Ref |
Expression |
1 |
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eldisjeqi.1 |
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2 |
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eldisjeq |
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3 |
1 2
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ax-mp |
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