Metamath Proof Explorer


Theorem elscottrank

Description: The rank of an element in a Scott's trick set. (Contributed by BTernaryTau, 8-Jul-2026)

Ref Expression
Assertion elscottrank ⊢ A ∈ Scott B → rank ⁡ A = ⋂ rank B

Proof

Step Hyp Ref Expression
1 fveqeq2 ⊢ x = A → rank ⁡ x = ⋂ rank B ↔ rank ⁡ A = ⋂ rank B
2 dfscott2 ⊢ Scott B = x ∈ B | rank ⁡ x = ⋂ rank B
3 1 2 elrab2 ⊢ A ∈ Scott B ↔ A ∈ B ∧ rank ⁡ A = ⋂ rank B
4 3 simprbi ⊢ A ∈ Scott B → rank ⁡ A = ⋂ rank B