Metamath Proof Explorer


Theorem elscottrank

Description: The rank of an element in a Scott's trick set. (Contributed by BTernaryTau, 8-Jul-2026)

Ref Expression
Assertion elscottrank ( 𝐴 ∈ Scott 𝐵 → ( rank ‘ 𝐴 ) = ( rank “ 𝐵 ) )

Proof

Step Hyp Ref Expression
1 fveqeq2 ( 𝑥 = 𝐴 → ( ( rank ‘ 𝑥 ) = ( rank “ 𝐵 ) ↔ ( rank ‘ 𝐴 ) = ( rank “ 𝐵 ) ) )
2 dfscott2 Scott 𝐵 = { 𝑥𝐵 ∣ ( rank ‘ 𝑥 ) = ( rank “ 𝐵 ) }
3 1 2 elrab2 ( 𝐴 ∈ Scott 𝐵 ↔ ( 𝐴𝐵 ∧ ( rank ‘ 𝐴 ) = ( rank “ 𝐵 ) ) )
4 3 simprbi ( 𝐴 ∈ Scott 𝐵 → ( rank ‘ 𝐴 ) = ( rank “ 𝐵 ) )