Metamath Proof Explorer


Theorem dfscott2

Description: Alternate definition of a Scott's trick set. (Contributed by BTernaryTau, 8-Jul-2026)

Ref Expression
Assertion dfscott2 Scott 𝐴 = { 𝑥𝐴 ∣ ( rank ‘ 𝑥 ) = ( rank “ 𝐴 ) }

Proof

Step Hyp Ref Expression
1 df-scott Scott 𝐴 = { 𝑥𝐴 ∣ ∀ 𝑦𝐴 ( rank ‘ 𝑥 ) ⊆ ( rank ‘ 𝑦 ) }
2 rankfn rank Fn V
3 ssv 𝐴 ⊆ V
4 fnfvintima ( ( rank Fn V ∧ 𝐴 ⊆ V ∧ 𝑥𝐴 ) → ( ( rank ‘ 𝑥 ) = ( rank “ 𝐴 ) ↔ ∀ 𝑦𝐴 ( rank ‘ 𝑥 ) ⊆ ( rank ‘ 𝑦 ) ) )
5 2 3 4 mp3an12 ( 𝑥𝐴 → ( ( rank ‘ 𝑥 ) = ( rank “ 𝐴 ) ↔ ∀ 𝑦𝐴 ( rank ‘ 𝑥 ) ⊆ ( rank ‘ 𝑦 ) ) )
6 5 rabbiia { 𝑥𝐴 ∣ ( rank ‘ 𝑥 ) = ( rank “ 𝐴 ) } = { 𝑥𝐴 ∣ ∀ 𝑦𝐴 ( rank ‘ 𝑥 ) ⊆ ( rank ‘ 𝑦 ) }
7 1 6 eqtr4i Scott 𝐴 = { 𝑥𝐴 ∣ ( rank ‘ 𝑥 ) = ( rank “ 𝐴 ) }