Metamath Proof Explorer


Theorem fnfvintima

Description: Condition for a function value to equal the intersection of an image that contains it. (Contributed by BTernaryTau, 23-Jun-2026)

Ref Expression
Assertion fnfvintima ( ( 𝐹 Fn 𝐴𝐵𝐴𝐶𝐵 ) → ( ( 𝐹𝐶 ) = ( 𝐹𝐵 ) ↔ ∀ 𝑥𝐵 ( 𝐹𝐶 ) ⊆ ( 𝐹𝑥 ) ) )

Proof

Step Hyp Ref Expression
1 eqimss ( ( 𝐹𝐶 ) = ( 𝐹𝐵 ) → ( 𝐹𝐶 ) ⊆ ( 𝐹𝐵 ) )
2 fnssintima ( ( 𝐹 Fn 𝐴𝐵𝐴 ) → ( ( 𝐹𝐶 ) ⊆ ( 𝐹𝐵 ) ↔ ∀ 𝑥𝐵 ( 𝐹𝐶 ) ⊆ ( 𝐹𝑥 ) ) )
3 2 3adant3 ( ( 𝐹 Fn 𝐴𝐵𝐴𝐶𝐵 ) → ( ( 𝐹𝐶 ) ⊆ ( 𝐹𝐵 ) ↔ ∀ 𝑥𝐵 ( 𝐹𝐶 ) ⊆ ( 𝐹𝑥 ) ) )
4 1 3 imbitrid ( ( 𝐹 Fn 𝐴𝐵𝐴𝐶𝐵 ) → ( ( 𝐹𝐶 ) = ( 𝐹𝐵 ) → ∀ 𝑥𝐵 ( 𝐹𝐶 ) ⊆ ( 𝐹𝑥 ) ) )
5 3 biimprd ( ( 𝐹 Fn 𝐴𝐵𝐴𝐶𝐵 ) → ( ∀ 𝑥𝐵 ( 𝐹𝐶 ) ⊆ ( 𝐹𝑥 ) → ( 𝐹𝐶 ) ⊆ ( 𝐹𝐵 ) ) )
6 fnfvima ( ( 𝐹 Fn 𝐴𝐵𝐴𝐶𝐵 ) → ( 𝐹𝐶 ) ∈ ( 𝐹𝐵 ) )
7 intss1 ( ( 𝐹𝐶 ) ∈ ( 𝐹𝐵 ) → ( 𝐹𝐵 ) ⊆ ( 𝐹𝐶 ) )
8 6 7 syl ( ( 𝐹 Fn 𝐴𝐵𝐴𝐶𝐵 ) → ( 𝐹𝐵 ) ⊆ ( 𝐹𝐶 ) )
9 5 8 jctird ( ( 𝐹 Fn 𝐴𝐵𝐴𝐶𝐵 ) → ( ∀ 𝑥𝐵 ( 𝐹𝐶 ) ⊆ ( 𝐹𝑥 ) → ( ( 𝐹𝐶 ) ⊆ ( 𝐹𝐵 ) ∧ ( 𝐹𝐵 ) ⊆ ( 𝐹𝐶 ) ) ) )
10 eqss ( ( 𝐹𝐶 ) = ( 𝐹𝐵 ) ↔ ( ( 𝐹𝐶 ) ⊆ ( 𝐹𝐵 ) ∧ ( 𝐹𝐵 ) ⊆ ( 𝐹𝐶 ) ) )
11 9 10 imbitrrdi ( ( 𝐹 Fn 𝐴𝐵𝐴𝐶𝐵 ) → ( ∀ 𝑥𝐵 ( 𝐹𝐶 ) ⊆ ( 𝐹𝑥 ) → ( 𝐹𝐶 ) = ( 𝐹𝐵 ) ) )
12 4 11 impbid ( ( 𝐹 Fn 𝐴𝐵𝐴𝐶𝐵 ) → ( ( 𝐹𝐶 ) = ( 𝐹𝐵 ) ↔ ∀ 𝑥𝐵 ( 𝐹𝐶 ) ⊆ ( 𝐹𝑥 ) ) )