Metamath Proof Explorer


Theorem ordprcon

Description: If an ordinal class is not a set, then it must be the proper class of all ordinals. (Contributed by BTernaryTau, 9-Jun-2026)

Ref Expression
Assertion ordprcon ( ( Ord 𝐴 ∧ ¬ 𝐴 ∈ V ) → 𝐴 = On )

Proof

Step Hyp Ref Expression
1 ordeleqon ( Ord 𝐴 ↔ ( 𝐴 ∈ On ∨ 𝐴 = On ) )
2 1 birani ( ( Ord 𝐴 ∧ ¬ 𝐴 ∈ V ) → ( 𝐴 ∈ On ∨ 𝐴 = On ) )
3 prcnel ( ¬ 𝐴 ∈ V → ¬ 𝐴 ∈ On )
4 3 adantl ( ( Ord 𝐴 ∧ ¬ 𝐴 ∈ V ) → ¬ 𝐴 ∈ On )
5 2 4 orcnd ( ( Ord 𝐴 ∧ ¬ 𝐴 ∈ V ) → 𝐴 = On )