Metamath Proof Explorer


Theorem ordprcon

Description: If an ordinal class is not a set, then it must be the proper class of all ordinals. (Contributed by BTernaryTau, 9-Jun-2026)

Ref Expression
Assertion ordprcon
|- ( ( Ord A /\ -. A e. _V ) -> A = On )

Proof

Step Hyp Ref Expression
1 ordeleqon
 |-  ( Ord A <-> ( A e. On \/ A = On ) )
2 1 birani
 |-  ( ( Ord A /\ -. A e. _V ) -> ( A e. On \/ A = On ) )
3 prcnel
 |-  ( -. A e. _V -> -. A e. On )
4 3 adantl
 |-  ( ( Ord A /\ -. A e. _V ) -> -. A e. On )
5 2 4 orcnd
 |-  ( ( Ord A /\ -. A e. _V ) -> A = On )