Metamath Proof Explorer


Theorem intss1

Description: An element of a class includes the intersection of the class. Exercise 4 of TakeutiZaring p. 44 (with correction), generalized to classes. (Contributed by NM, 18-Nov-1995)

Ref Expression
Assertion intss1 ( 𝐴 ∈ 𝐵 → ∩ 𝐵 ⊆ 𝐴 )

Proof

Step Hyp Ref Expression
1 vex ⊢ 𝑥 ∈ V
2 1 elint ⊢ ( 𝑥 ∈ ∩ 𝐵 ↔ ∀ 𝑦 ( 𝑦 ∈ 𝐵 → 𝑥 ∈ 𝑦 ) )
3 eleq1 ⊢ ( 𝑦 = 𝐴 → ( 𝑦 ∈ 𝐵 ↔ 𝐴 ∈ 𝐵 ) )
4 eleq2 ⊢ ( 𝑦 = 𝐴 → ( 𝑥 ∈ 𝑦 ↔ 𝑥 ∈ 𝐴 ) )
5 3 4 imbi12d ⊢ ( 𝑦 = 𝐴 → ( ( 𝑦 ∈ 𝐵 → 𝑥 ∈ 𝑦 ) ↔ ( 𝐴 ∈ 𝐵 → 𝑥 ∈ 𝐴 ) ) )
6 5 spcgv ⊢ ( 𝐴 ∈ 𝐵 → ( ∀ 𝑦 ( 𝑦 ∈ 𝐵 → 𝑥 ∈ 𝑦 ) → ( 𝐴 ∈ 𝐵 → 𝑥 ∈ 𝐴 ) ) )
7 6 pm2.43a ⊢ ( 𝐴 ∈ 𝐵 → ( ∀ 𝑦 ( 𝑦 ∈ 𝐵 → 𝑥 ∈ 𝑦 ) → 𝑥 ∈ 𝐴 ) )
8 2 7 biimtrid ⊢ ( 𝐴 ∈ 𝐵 → ( 𝑥 ∈ ∩ 𝐵 → 𝑥 ∈ 𝐴 ) )
9 8 ssrdv ⊢ ( 𝐴 ∈ 𝐵 → ∩ 𝐵 ⊆ 𝐴 )