Metamath Proof Explorer
Description: Any set is equal to its preimage under the converse membership relation.
(Contributed by Mario Carneiro, 9-Mar-2013)
|
|
Ref |
Expression |
|
Hypothesis |
epini.1 |
|
|
Assertion |
epini |
|
Proof
Step |
Hyp |
Ref |
Expression |
1 |
|
epini.1 |
|
2 |
|
vex |
|
3 |
2
|
eliniseg |
|
4 |
1 3
|
ax-mp |
|
5 |
1
|
epeli |
|
6 |
4 5
|
bitri |
|
7 |
6
|
eqriv |
|