Metamath Proof Explorer


Theorem epini

Description: Any set is equal to its preimage under the converse membership relation. (Contributed by Mario Carneiro, 9-Mar-2013)

Ref Expression
Hypothesis epini.1 A V
Assertion epini E -1 A = A

Proof

Step Hyp Ref Expression
1 epini.1 A V
2 vex x V
3 2 eliniseg A V x E -1 A x E A
4 1 3 ax-mp x E -1 A x E A
5 1 epeli x E A x A
6 4 5 bitri x E -1 A x A
7 6 eqriv E -1 A = A