Metamath Proof Explorer


Theorem epin

Description: Any set is equal to its preimage under the converse membership relation. (Contributed by Mario Carneiro, 9-Mar-2013) Put in closed form. (Revised by BJ, 16-Oct-2024)

Ref Expression
Assertion epin ⊢ A ∈ V → E -1 A = A

Proof

Step Hyp Ref Expression
1 vex ⊢ x ∈ V
2 1 eliniseg ⊢ A ∈ V → x ∈ E -1 A ↔ x E A
3 epelg ⊢ A ∈ V → x E A ↔ x ∈ A
4 2 3 bitrd ⊢ A ∈ V → x ∈ E -1 A ↔ x ∈ A
5 4 eqrdv ⊢ A ∈ V → E -1 A = A