Metamath Proof Explorer


Theorem epin

Description: Any set is equal to its preimage under the converse membership relation. (Contributed by Mario Carneiro, 9-Mar-2013) Put in closed form. (Revised by BJ, 16-Oct-2024)

Ref Expression
Assertion epin ( 𝐴𝑉 → ( E “ { 𝐴 } ) = 𝐴 )

Proof

Step Hyp Ref Expression
1 vex 𝑥 ∈ V
2 1 eliniseg ( 𝐴𝑉 → ( 𝑥 ∈ ( E “ { 𝐴 } ) ↔ 𝑥 E 𝐴 ) )
3 epelg ( 𝐴𝑉 → ( 𝑥 E 𝐴𝑥𝐴 ) )
4 2 3 bitrd ( 𝐴𝑉 → ( 𝑥 ∈ ( E “ { 𝐴 } ) ↔ 𝑥𝐴 ) )
5 4 eqrdv ( 𝐴𝑉 → ( E “ { 𝐴 } ) = 𝐴 )