Metamath Proof Explorer


Theorem eqfnfv2d2

Description: Equality of functions is determined by their values, a deduction version. (Contributed by metakunt, 28-May-2024)

Ref Expression
Hypotheses eqfnfv2d2.1 ⊢ φ → F Fn A
eqfnfv2d2.2 ⊢ φ → G Fn B
eqfnfv2d2.3 ⊢ φ → A = B
eqfnfv2d2.4 ⊢ φ ∧ x ∈ A → F ⁡ x = G ⁡ x
Assertion eqfnfv2d2 ⊢ φ → F = G

Proof

Step Hyp Ref Expression
1 eqfnfv2d2.1 ⊢ φ → F Fn A
2 eqfnfv2d2.2 ⊢ φ → G Fn B
3 eqfnfv2d2.3 ⊢ φ → A = B
4 eqfnfv2d2.4 ⊢ φ ∧ x ∈ A → F ⁡ x = G ⁡ x
5 4 ralrimiva ⊢ φ → ∀ x ∈ A F ⁡ x = G ⁡ x
6 3 5 jca ⊢ φ → A = B ∧ ∀ x ∈ A F ⁡ x = G ⁡ x
7 1 2 jca ⊢ φ → F Fn A ∧ G Fn B
8 eqfnfv2 ⊢ F Fn A ∧ G Fn B → F = G ↔ A = B ∧ ∀ x ∈ A F ⁡ x = G ⁡ x
9 7 8 syl ⊢ φ → F = G ↔ A = B ∧ ∀ x ∈ A F ⁡ x = G ⁡ x
10 6 9 mpbird ⊢ φ → F = G