Metamath Proof Explorer


Theorem fzsplitnd

Description: Split a finite interval of integers into two parts. (Contributed by metakunt, 28-May-2024)

Ref Expression
Hypothesis fzsplitnd.1 ⊢ φ → K ∈ M … N
Assertion fzsplitnd ⊢ φ → M … N = M … K − 1 ∪ K … N

Proof

Step Hyp Ref Expression
1 fzsplitnd.1 ⊢ φ → K ∈ M … N
2 elfzuz ⊢ K ∈ M … N → K ∈ ℤ ≥ M
3 1 2 syl ⊢ φ → K ∈ ℤ ≥ M
4 1 elfzelzd ⊢ φ → K ∈ ℤ
5 4 zcnd ⊢ φ → K ∈ ℂ
6 1cnd ⊢ φ → 1 ∈ ℂ
7 5 6 npcand ⊢ φ → K - 1 + 1 = K
8 7 eleq1d ⊢ φ → K - 1 + 1 ∈ ℤ ≥ M ↔ K ∈ ℤ ≥ M
9 3 8 mpbird ⊢ φ → K - 1 + 1 ∈ ℤ ≥ M
10 1zzd ⊢ φ → 1 ∈ ℤ
11 4 10 zsubcld ⊢ φ → K − 1 ∈ ℤ
12 elfzuz3 ⊢ K ∈ M … N → N ∈ ℤ ≥ K
13 1 12 syl ⊢ φ → N ∈ ℤ ≥ K
14 7 fveq2d ⊢ φ → ℤ ≥ K - 1 + 1 = ℤ ≥ K
15 14 eleq2d ⊢ φ → N ∈ ℤ ≥ K - 1 + 1 ↔ N ∈ ℤ ≥ K
16 13 15 mpbird ⊢ φ → N ∈ ℤ ≥ K - 1 + 1
17 peano2uzr ⊢ K − 1 ∈ ℤ ∧ N ∈ ℤ ≥ K - 1 + 1 → N ∈ ℤ ≥ K − 1
18 11 16 17 syl2anc ⊢ φ → N ∈ ℤ ≥ K − 1
19 fzsplit2 ⊢ K - 1 + 1 ∈ ℤ ≥ M ∧ N ∈ ℤ ≥ K − 1 → M … N = M … K − 1 ∪ K - 1 + 1 … N
20 9 18 19 syl2anc ⊢ φ → M … N = M … K − 1 ∪ K - 1 + 1 … N
21 7 oveq1d ⊢ φ → K - 1 + 1 … N = K … N
22 21 uneq2d ⊢ φ → M … K − 1 ∪ K - 1 + 1 … N = M … K − 1 ∪ K … N
23 20 22 eqtrd ⊢ φ → M … N = M … K − 1 ∪ K … N