Metamath Proof Explorer


Theorem oveq1d

Description: Equality deduction for operation value. (Contributed by NM, 13-Mar-1995)

Ref Expression
Hypothesis oveq1d.1 φ A = B
Assertion oveq1d φ A F C = B F C

Proof

Step Hyp Ref Expression
1 oveq1d.1 φ A = B
2 oveq1 A = B A F C = B F C
3 1 2 syl φ A F C = B F C