Metamath Proof Explorer


Theorem eqop2

Description: Two ways to express equality with an ordered pair. (Contributed by NM, 25-Feb-2014)

Ref Expression
Hypotheses eqop2.1 ⊢ B ∈ V
eqop2.2 ⊢ C ∈ V
Assertion eqop2 ⊢ A = B C ↔ A ∈ V × V ∧ 1 st ⁡ A = B ∧ 2 nd ⁡ A = C

Proof

Step Hyp Ref Expression
1 eqop2.1 ⊢ B ∈ V
2 eqop2.2 ⊢ C ∈ V
3 1 2 opelvv ⊢ B C ∈ V × V
4 eleq1 ⊢ A = B C → A ∈ V × V ↔ B C ∈ V × V
5 3 4 mpbiri ⊢ A = B C → A ∈ V × V
6 eqop ⊢ A ∈ V × V → A = B C ↔ 1 st ⁡ A = B ∧ 2 nd ⁡ A = C
7 5 6 biadanii ⊢ A = B C ↔ A ∈ V × V ∧ 1 st ⁡ A = B ∧ 2 nd ⁡ A = C