Metamath Proof Explorer


Theorem eqsqrt2d

Description: A deduction for showing that a number equals the square root of another. (Contributed by Mario Carneiro, 3-Apr-2015)

Ref Expression
Hypotheses eqsqrtd.1 ⊢ φ → A ∈ ℂ
eqsqrtd.2 ⊢ φ → B ∈ ℂ
eqsqrtd.3 ⊢ φ → A 2 = B
eqsqrt2d.4 ⊢ φ → 0 < ℜ ⁡ A
Assertion eqsqrt2d ⊢ φ → A = B

Proof

Step Hyp Ref Expression
1 eqsqrtd.1 ⊢ φ → A ∈ ℂ
2 eqsqrtd.2 ⊢ φ → B ∈ ℂ
3 eqsqrtd.3 ⊢ φ → A 2 = B
4 eqsqrt2d.4 ⊢ φ → 0 < ℜ ⁡ A
5 0re ⊢ 0 ∈ ℝ
6 1 recld ⊢ φ → ℜ ⁡ A ∈ ℝ
7 ltle ⊢ 0 ∈ ℝ ∧ ℜ ⁡ A ∈ ℝ → 0 < ℜ ⁡ A → 0 ≤ ℜ ⁡ A
8 5 6 7 sylancr ⊢ φ → 0 < ℜ ⁡ A → 0 ≤ ℜ ⁡ A
9 4 8 mpd ⊢ φ → 0 ≤ ℜ ⁡ A
10 reim ⊢ A ∈ ℂ → ℜ ⁡ A = ℑ ⁡ i ⁢ A
11 1 10 syl ⊢ φ → ℜ ⁡ A = ℑ ⁡ i ⁢ A
12 4 gt0ne0d ⊢ φ → ℜ ⁡ A ≠ 0
13 11 12 eqnetrrd ⊢ φ → ℑ ⁡ i ⁢ A ≠ 0
14 rpre ⊢ i ⁢ A ∈ ℝ + → i ⁢ A ∈ ℝ
15 14 reim0d ⊢ i ⁢ A ∈ ℝ + → ℑ ⁡ i ⁢ A = 0
16 15 necon3ai ⊢ ℑ ⁡ i ⁢ A ≠ 0 → ¬ i ⁢ A ∈ ℝ +
17 13 16 syl ⊢ φ → ¬ i ⁢ A ∈ ℝ +
18 1 2 3 9 17 eqsqrtd ⊢ φ → A = B