Metamath Proof Explorer


Theorem eqssi

Description: Infer equality from two subclass relationships. Compare Theorem 4 of Suppes p. 22. (Contributed by NM, 9-Sep-1993)

Ref Expression
Hypotheses eqssi.1 A B
eqssi.2 B A
Assertion eqssi A = B

Proof

Step Hyp Ref Expression
1 eqssi.1 A B
2 eqssi.2 B A
3 eqss A = B A B B A
4 1 2 3 mpbir2an A = B