Metamath Proof Explorer


Theorem equequ1

Description: An equivalence law for equality. (Contributed by NM, 1-Aug-1993) (Proof shortened by Wolf Lammen, 10-Dec-2017)

Ref Expression
Assertion equequ1 ⊢ x = y → x = z ↔ y = z

Proof

Step Hyp Ref Expression
1 ax7 ⊢ x = y → x = z → y = z
2 equtr ⊢ x = y → y = z → x = z
3 1 2 impbid ⊢ x = y → x = z ↔ y = z